=z^2-(1-i)z-i

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Solution for =z^2-(1-i)z-i equation:


Simplifying
0 = z2 + -1(1 + -1i) * z + -1i

Reorder the terms for easier multiplication:
0 = z2 + -1z(1 + -1i) + -1i
0 = z2 + (1 * -1z + -1i * -1z) + -1i

Reorder the terms:
0 = z2 + (1iz + -1z) + -1i
0 = z2 + (1iz + -1z) + -1i

Reorder the terms:
0 = -1i + 1iz + -1z + z2

Solving
0 = -1i + 1iz + -1z + z2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'i' to each side of the equation.
0 + i = -1i + 1iz + -1z + i + z2
Remove the zero:
i = -1i + 1iz + -1z + i + z2

Reorder the terms:
i = -1i + i + 1iz + -1z + z2

Combine like terms: -1i + i = 0
i = 0 + 1iz + -1z + z2
i = 1iz + -1z + z2

Add '-1iz' to each side of the equation.
i + -1iz = 1iz + -1z + -1iz + z2

Reorder the terms:
i + -1iz = 1iz + -1iz + -1z + z2

Combine like terms: 1iz + -1iz = 0
i + -1iz = 0 + -1z + z2
i + -1iz = -1z + z2

Reorder the terms:
i + -1iz + z + -1z2 = -1z + z + z2 + -1z2

Combine like terms: -1z + z = 0
i + -1iz + z + -1z2 = 0 + z2 + -1z2
i + -1iz + z + -1z2 = z2 + -1z2

Combine like terms: z2 + -1z2 = 0
i + -1iz + z + -1z2 = 0

The solution to this equation could not be determined.

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